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Old 10-21-05, 12:00 AM   #1
Willa
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help with math

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i never go so i have no idea how to do this lol
solve each system by substitution
v= u - 5
v= 3u + 7
umm anyone know liek the steps to solving these types of problems lol
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Old 10-21-05, 01:39 AM   #2
Mentalz
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Fuck if I know, I forgot math, thats why I joined the military

However i'll give it a try


v= u - 5
+5 +5
v +5 = u +5
u = 0



I *think* (or the lack of thinking)

I do know what ever you do to one side you have to do to the other aswell
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Old 10-21-05, 01:50 AM   #3
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Ok heres how you do them both:

Quote:
In this instance we replace "v" with "x" and we replace "u" with "y".

x = y -5


x = 3y +7


Quote:
EXAMPLE =NOT THE SAME PROBLEM, BUT THIS IS THE METHOD USED=
1. Solve one of the equations for either "x =" or "y =".
This example solves the second equation for "y =".



3y - 2x = 11
y = 9 - 2x


2. Replace the "y" value in the first equation by what "y" now equals. Grab the "y" value and plug it into the other equation.



3(9 - 2x) - 2x = 11


3. Solve this new equation for "x".



(27 - 6x) - 2x = 11
27 - 6x - 2x = 11
27 - 8x = 11
-8x = -16
x = 2

4. Place this new "x" value into either of the ORIGINAL equations in order to solve for "y". Pick the easier one to work with!


y = 9 - 2(2)
y = 9 - 4
y = 5


5. Check: substitute x = 2 and y = 5 into BOTH ORIGINAL equations. If these answers are correct, BOTH equations will be TRUE!

3y - 2x = 11
3(5) - 2(2) = 11
15 - 4 = 11
11 = 11 (check!)

y + 2x = 9
5 + 2(2) = 9
5 + 4 = 9
9 = 9 (check!)
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Old 10-21-05, 01:51 AM   #4
Shazz
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WTF!!
slow down..
Holy shit.
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Old 10-21-05, 01:57 AM   #5
Mentalz
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In this instance we replace "v" with "x" and we replace "u" with "y".

x = y -5


x = 3y +7

I do that just to make it easier for me to understand.

Lets solve.


x = y -5

Substituation means you substitute side for side... So, if you want to solve for X (v) you need to add 5 to the right side to counter the negative 5.

'x = y -5
'+5 +5'

x +5 = y

y = 0

or U = 0
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Old 10-21-05, 08:40 AM   #6
Willa
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fuck this shit lol u have to get a y and an x value : /
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